Absolute Converter

Convert from
dBmA with Z = Ω  
 

dBμV

=
\(dBmA + 20 \cdot log_{10}(Z)+60 \)

dBmV

=
\(dBmA + 20 \cdot log_{10}(Z)\)

dBV

=
\(dBmA+20 \cdot log_{10}(Z)-60\)

dBμA

=
\( dBmA+60\)

dBA

=
\( dBmA-60 \)

dBpW

=
\( dBmA+10 \cdot log_{10}(Z)+60 \)

dBm

=
\( dBmA+10 \cdot log_{10}(Z)-30 \)

dBW

=
\( dBmA+10 \cdot log_{10}(Z)-60 \)
 

μV

=
\( 10^{(dBmA+20 \cdot log_{10}(Z)+60)/20} \)

mV

=
\( 10^{(dBmA+20 \cdot log_{10}(Z))/20}\)

V

=
\( 10^{(dBmA+20 \cdot log_{10}(Z)-60)/20} \)

μA

=
\( 10^{(dBmA+60)/20}\)

mA

=
\( 10^{dBmA/20}\)

A

=
\( 10^{(dBmA-60)/20} \)

pW

=
\( 10^{(dBμA+10 \cdot log_{10}(Z)+60)/10} \)

mW

=
\( 10^{(dBμA+10 \cdot log_{10}(Z)-30)/10} \)

W

=
\( 10^{(dBμA+10 \cdot log_{10}(Z)-60)/10} \)
 
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