Absolute Converter

Convert from
dBμA with Z = Ω  
 

dBμV

=
\(dB\mu A + 20\cdot log_{10}(Z)\)

dBmV

=
\(dB\mu A + 20\cdot log_{10}(Z)- 60 \)

dBV

=
\(dB\mu A + 20\cdot log_{10}(Z)-120)\)

dBmA

=
\( dB\mu A-60 \)

dBA

=
\( dB\mu A-120 \)

dBpW

=
\( dB\mu A-10 \cdot log_{10}(Z) \)

dBm

=
\( dB\mu A-10 \cdot log_{10}(Z)-90 \)

dBW

=
\( dB\mu A-10 \cdot log_{10}(Z)-120 \)
 

μV

=
\( 10^{(dB\mu A-20 \cdot log_{10}(Z))/20} \)

mV

=
\( 10^{(dB\mu A-20 \cdot log_{10}(Z)-60)/20} \)

V

=
\( 10^{(dB\mu A+20 \cdot log_{10}(Z)-120)/20} \)

μA

=
\( 10^{dB\mu A/20}\)

mA

=
\( 10^{(dB\mu A-60)/20} \)

A

=
\( 10^{(dB\mu A-120)/20} \)

pW

=
\( 10^{(dB\mu A-10 \cdot log_{10}(Z))/10} \)

mW

=
\( 10^{(dB\mu A-10 \cdot log_{10}(Z)-90)/10} \)

W

=
\( 10^{(dB\mu A-10 \cdot log_{10}(Z)-120)/10} \)
 
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