Convert from
mW with Z = Ω  
 

dBμV

=
\( 10 \cdot log_{10}(mW \cdot Z) + 90\)

dBmV

=
\( 10 \cdot log_{10}(mW \cdot Z) + 30 \)

dBV

=
\( 10 \cdot log_{10}(mW \cdot Z) - 30 \)

dBμA

=
\( 10 \cdot log_{10}(mW / Z) + 90 \)

dBmA

=
\( 10 \cdot log_{10}(mW / Z) + 30 \)

dBpW

=
\( 10 \cdot log_{10}(mW / Z) - 30 \)

dBA

=
\( 10 \cdot log_{10}(mW) + 90 \)

dBm

=
\( 10 \cdot log_{10}(mW) \)

dBW

=
\( 10 \cdot log_{10}(mW) - 30 \)
 

μV

=
\( \sqrt{mW \cdot Z \cdot 10^{-3} } \cdot 10^6 \)

mV

=
\( \sqrt{mW \cdot Z \cdot 10^{-3} } \cdot 10^3 \)

V

=
\( \sqrt{mW \cdot Z \cdot 10^{-3} } \)

μA

=
\( \sqrt{ \frac{ mW }{ Z } \cdot 10^{-3} } \cdot 10^6 \)

mA

=
\( \sqrt{ \frac{ mW }{ Z } \cdot 10^{-3} } \cdot 10^3 \)

A

=
\( \sqrt{ \frac{ mW }{ Z } \cdot 10^{-3} } \)

pW

=
\( mW \cdot 10^9 \)

W

=
\( mW \cdot 10^{-3} \)
 

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