Absolute Converter

Convert from
dBV with Z = Ω  
 

dBμV

=
\(dBV + 120\)

dBmV

=
\(dBV + 60 \)

dBμA

=
\(dBV-20 \cdot log_{10}(Z) + 120\)

dBmA

=
\( dBV-20 \cdot log_{10}(Z)+60 \)

dBA

=
\( dBV -20 \cdot log_{10}(Z) \)

dBpW

=
\( dBV -10 \cdot log_{10}(Z)+120\)

dBm

=
\( dBV-10 \cdot log_{10}(Z)+30 \)

dBW

=
\( dBV-10 \cdot log_{10}(Z) \)
 

μV

=
\( 10^{(dBV+120)/20} \)

mV

=
\( 10^{(dBV+60)/20} \)

V

=
\( 10^{dBV/20}\)

μA

=
\( 10^{(dBV-20 \cdot log_{10}(Z)+120)/20} \)

mA

=
\( 10^{(dBV-20 \cdot log_{10}(Z)+60)/20} \)

A

=
\( 10^{(dBV -20 \cdot log_{10}(Z))/20} \)

pW

=
\( \frac{(10^{(dBV /20)})^2}{Z}\cdot 10^{12} \)

mW

=
\( \frac{(10^{(dBV/20)})^2}{Z}\cdot 10^{3} \)

W

=
\( \frac{(10^{(dBV/20)})^2}{Z} \)
 
Loading...