Absolute Converter
Convert from
V with Z = Ω  
 

dBμV

=
\( 20 \cdot log_{10}(V) + 120 \)

dBmV

=
\( 20 \cdot log_{10}(V) + 60 \)

dBV

=
\( 20 \cdot log_{10}(V) \)

dBμA

=
\( 20 \cdot log_{10}(V) - 20 \cdot log_{10}(Z) + 120 \)

dBmA

=
\( 20 \cdot log_{10}(V) - 20 \cdot log_{10}(Z) + 60 \)

dBA

=
\( 20 \cdot log_{10}(V) - 20 \cdot log_{10}(Z) \)

dBpW

=
\( 20 \cdot log_{10}(V) - 10 \cdot log_{10}(Z) + 120 \)

dBm

=
\( 20 \cdot log_{10}(V) - 10 \cdot log_{10}(Z) + 30 \)

dBW

=
\( 20 \cdot log_{10}(V) - 10 \cdot log_{10}(Z)\)
 

μV

=
\( V \cdot 10^6 \)

mV

=
\( V \cdot 10^3 \)

μA

=
\( \frac{ V }{ Z } \cdot 10^6 \)

mA

=
\( \frac{ V }{ Z } \cdot 10^3 \)

A

=
\( \frac{ V }{ Z } \)

pW

=
\( \frac{ V^2 }{ Z } \cdot 10^12 \)

mW

=
\( \frac{ V^2 }{ Z } \cdot 10^3 \)

W

=
\( \frac{ V^2 }{ Z } \)
 
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