Absolute Converter

Convert from
dBm with Z = Ω  
 

dBμV

=
\( dBm + 10 \cdot log_{10}(Z) + 90 \)

dBmV

=
\( dBm + 10 \cdot log_{10}(Z) + 30 \)

dBV

=
\( dBm + 10 \cdot log_{10}(Z) - 30 \)

dBμA

=
\( dBm - 10 \cdot log_{10}(Z) + 90 \)

dBmA

=
\( dBm - 10 \cdot log_{10}(Z) + 30 \)

dBA

=
\( dBm - 10 \cdot log_{10}(Z) \)

dBpW

=
\( dBm + 90 \)

dBW

=
\( dBm - 30 \)
 

μV

=
\( \sqrt{10^{dBm/10} \cdot Z \cdot 10^{-3} } \cdot 10^6 \)

mV

=
\( \sqrt{10^{dBm/10} \cdot Z \cdot 10^{-3} } \cdot 10^3 \)

V

=
\( \sqrt{10^{dBm/10} \cdot Z \cdot 10^{-3} } \)

μA

=
\( \sqrt{ \frac{10^{dBm/10}} {Z} \cdot 10^{-3} } \cdot 10^6 \)

mA

=
\( \sqrt{ \frac{10^{dBm/10}} {Z} \cdot 10^{-3} } \cdot 10^3 \)

A

=
\( \sqrt{ \frac{10^{dBm/10}} {Z} \cdot 10^{-3} } \)

pW

=
\( 10^{(dBm+90)/10} \)

mW

=
\( 10^{dBm/10} \)

W

=
\( 10^{(dBm-30)/10} \)
 
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