Absolute Converter

Convert from
dBW with Z = Ω  
 

dBμV

=
\( dBW + 10 \cdot log_{10}(Z) + 120 \)

dBmV

=
\( dBW + 10 \cdot log_{10}(Z) + 60 \)

dBV

=
\( dBW + 10 \cdot log_{10}(Z) \)

dBμA

=
\( dBW - 10 \cdot log_{10}(Z) + 120 \)

dBmA

=
\( dBW - 10 \cdot log_{10}(Z) + 60 \)

dBA

=
\( dBW - 10 \cdot log_{10}(Z) \)

dBpW

=
\( dBW + 120 \)

dBm

=
\( dBW + 30 \)
 

μV

=
\( \sqrt{10^{dBW/10} \cdot Z} \cdot 10^6 \)

mV

=
\( \sqrt{10^{dBW/10} \cdot Z} \cdot 10^3 \)

V

=
\( \sqrt{10^{dBW/10} \cdot Z} \)

μA

=
\( \sqrt{ \frac{10^{dBW/10}} {Z}} \cdot 10^6 \)

mA

=
\( \sqrt{ \frac{10^{dBW/10}} {Z}} \cdot 10^3 \)

A

=
\( \sqrt{ \frac{10^{dBW/10}} {Z}} \)

pW

=
\( 10^{(dBW+120)/10} \)

mW

=
\( 10^{(dBW+30)/10} \)

W

=
\( 10^{dBW/10} \)
 
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