Convert from
W with Z = Ω  
 

dBμV

=
\( 10 \cdot log_{10}(W \cdot Z) + 120 \)

dBmV

=
\( 10 \cdot log_{10}(W \cdot Z) + 60 \)

dBV

=
\( 10 \cdot log_{10}(W \cdot Z) \)

dBμA

=
\( 10 \cdot log_{10}(W / Z) + 120 \)

dBmA

=
\( 10 \cdot log_{10}(W / Z) + 60 \)

dBA

=
\( 10 \cdot log_{10}(W / Z) \)

dBpW

=
\( 10 \cdot log_{10}(W) + 120 \)

dBm

=
\( 10 \cdot log_{10}(W) + 30 \)

dBW

=
\( 10 \cdot log_{10}(W) \)
 

μV

=
\( \sqrt{W \cdot Z } \cdot 10^6 \)

mV

=
\( \sqrt{W \cdot Z } \cdot 10^3 \)

V

=
\( \sqrt{W \cdot Z } \)

μA

=
\( \sqrt{ \frac{ W }{ Z } } \cdot 10^6 \)

mA

=
\( \sqrt{ \frac{ W }{ Z } } \cdot 10^3 \)

A

=
\( \sqrt{ \frac{ W }{ Z } } \)

pW

=
\( W \cdot 10^{12} \)

mW

=
\( W \cdot 10^3 \)
 

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